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Thread: partial fractions

  1. March 26th 2009, 05:19 PM #1
    qzno
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    partial fractions

    \int \frac{3x^5 - 7x^4 - 27x^3 + 28x^2 + 16}{x^3 - 4x^2} dx

    where the degree of the numerator is higher than the denominator, i thought i had to do polynomial long division so i got:

    <br /> \int 3x^2 + 5x - 7 + \frac{16}{x^3-4x^2} dx

    and im now at this point and am stuck


    <br /> x^3 + \frac{5x^2}{2} - 7x + 16\int \frac{1}{x^2(x-4)} dx
    Last edited by qzno; March 26th 2009 at 05:36 PM.
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  2. March 26th 2009, 06:11 PM #2
    skeeter
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    put the 16 back.

    repeated linear factor ...

    \frac{16}{x^2(x-4)} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x-4}

    A = -1 , B = -4 , C = 1
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