
partial fractions
$\displaystyle \int \frac{3x^5  7x^4  27x^3 + 28x^2 + 16}{x^3  4x^2} dx$
where the degree of the numerator is higher than the denominator, i thought i had to do polynomial long division so i got:
$\displaystyle
\int 3x^2 + 5x  7 + \frac{16}{x^34x^2} dx$
and im now at this point and am stuck
$\displaystyle
x^3 + \frac{5x^2}{2}  7x + 16\int \frac{1}{x^2(x4)} dx$

put the 16 back.
repeated linear factor ...
$\displaystyle \frac{16}{x^2(x4)} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x4}$
$\displaystyle A = 1$ , $\displaystyle B = 4$ , $\displaystyle C = 1$