How to find the point on the curve nearest to A(3,0)?

**AlphaRock** · March 26th 2009, 05:16 PM

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**skeeter** · March 26th 2009, 05:22 PM

Originally Posted by AlphaRock

Given: f(x) = -(x^2).

Find the point on the curve that is nearest to A(3,0).

Can somebody show me how we do this?

point on the curve ... $(x,-x^2)$

distance formula ...

$D = \sqrt{(x-3)^2 + (-x^2 - 0)^2}$

$D = \sqrt{x^4 + x^2 - 6x + 9}$

if $x^4 + x^2 - 6x + 9$ is minimized, then so is D.

**AlphaRock** · March 26th 2009, 05:57 PM

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