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Last edited by AlphaRock; Apr 1st 2009 at 01:44 AM.
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Originally Posted by AlphaRock Given: f(x) = -(x^2). Find the point on the curve that is nearest to A(3,0). Can somebody show me how we do this? point on the curve ... $\displaystyle (x,-x^2)$ distance formula ... $\displaystyle D = \sqrt{(x-3)^2 + (-x^2 - 0)^2}$ $\displaystyle D = \sqrt{x^4 + x^2 - 6x + 9}$ if $\displaystyle x^4 + x^2 - 6x + 9$ is minimized, then so is D.
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Last edited by AlphaRock; Apr 1st 2009 at 01:45 AM.
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