i know it simplifies to x^8/3 - 4x^2/3 but how does one get to that (esp. the x^8/3)

also, how do you get to f'(x) from here?

Thank you in advance to those smarter than I...

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- Mar 26th 2009, 12:25 PMcalcconfusedf(x)=x^2/3 (x^2-4)...simplifiy then get f'(x)
i know it simplifies to x^8/3 - 4x^2/3 but how does one get to that (esp. the x^8/3)

also, how do you get to f'(x) from here?

Thank you in advance to those smarter than I... - Mar 26th 2009, 01:39 PMsinewave85