lim x to infinity - [ln(2+h) - ln 2]/h I'm so confused because there's no x in the limit equation. The answer, by the way, is 1/2. Please clarify how to solve the above problem. Thanks!
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Hi The derivative of ln(x) is 1/x therefore the derivative of ln(x) taken at x=2 is 1/2 In terms of limit you can write $\displaystyle \lim_{h \rightarrow 0} \frac{\ln(2+h) - \ln(2)}{h} = \frac12$
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