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Math Help - simple integration.

  1. #1
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    simple integration.

    The gradient of a curve is dy/dx=kx, where k is constant.
    y=6x-7 and y=mx+c are the equation of the tangent and normal to the curve respectively. Find the values of m and c.

    m is solved easily. but couldn't find out what's c.
    answer; c=-5/6
    Any help would be so much appreciated!
    Thank you in advance!
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  2. #2
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    Quote Originally Posted by z1llch View Post
    The gradient of a curve is dy/dx=kx, where k is constant.
    y=6x-7 and y=mx+c are the equation of the tangent and normal to the curve respectively. Find the values of m and c.

    m is solved easily. but couldn't find out what's c.
    answer; c=-5/6
    Any help would be so much appreciated!
    Thank you in advance!
    If dy/dx= kx, then y= \frac{1}{2}x^2+ C. If y= 6x- 7 is tangent to that, what is C and where is the line tangent to the curve? What must c be in order that y= mx+ c pass through that point?
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