i have the answer as f''(x)=12x^2 - 24x and i am not sure how/why i have that
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Do you mean $\displaystyle f(x)=x^{4}-4x^{3}$? If so: $\displaystyle f'(x)=4x^{3}-12x^{2}$ $\displaystyle f''(x)=12x^{2}-24x$
Originally Posted by Pinkk Do you mean $\displaystyle f(x)=x^{4}-4x^{3}$? If so: $\displaystyle f'(x)=4x^{3}-12x^{2}$ $\displaystyle f''(x)=12x^{2}-24x$ thats what i thought. i think my professor made an error. the original is f(x) = x^4 - 4x^3. he said then that f''(x) = 12x^2 - 24x. that made no sense to me...
Just take the derivative, then take the derivative of the derivative.
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