Umm.. is this right? Is there supposed to be a negative in front of the a^2 value? (Rule from Laplace charts says L{cos(at)}= s/(s^2+a^2)..

So.. yeah, just wondering if I'm messing this problem up, i've checked my work several times, but i thought you could pull a negative sign outside of a Laplace Transform (aka L{-f(t)}= -L{f(t)})

Thanks ahead of time guys, hope this isn't a hard one

I figured it out:

For anyone who makes the same mistake as me by rare chance, you must solve for the Quantity of "-INT{e^-st*sint}". I solved for the normal int and distributed the negative into my equations so my answer was wrong.