The "normal" is the perpendicular. So what is the "slope" of f(x) = x^2 at x = a? Then what is the slope of theperpendicular?

Use this slope and the given point tothe line equation.

Then plug "0" in for "x" to find they-interceptof this perpendicular line.

What expression do you get for the y-intercept? What limit do you get as a -> 0?

What are your thoughts...?