hey guys, really need help with calculus... its my last class i need to pass in order to gaduate and get

the dammed bachelors degree. any who...

the problem is that i dont understand anything i started doing the homework i need to finish today .. and got stuck on the first exercise here it is..

series of (3/n^2 - 16) n = 0 to infinity

$\displaystyle

\sum^{\infty}_{n=0} ({\frac{{\frac{3}{(n+1)^2 -16}}}{{\frac{3}{n^2 - 16}}}})

$

ok i know this is a Series P and P = 2 therefore is greater than 1 making this series converge

thing is i need to apply the ratio formula.. wich is :

limit(3/(((n+1)^2-16)*(3/(n^2-16))), n = infinity)

maple says the limit is 1, but when i do it manually i get -(12/15)

what am i doing wrong??

here are my steps

3

---------

(n+1)^2 -16

-----------

3

---------

n^2 - 16

ok so ...the 3's cancel each other out and you get

lim (n+1)^2 -16

----------

n^2 - 16

now you make a substitution, n = 1

lim (1+1) ^2 - 16

--------------

1^2 - 16

that turns into

lim 4 - 16

------

1 - 16

that equals

- 12/15

now... -12/15 is not 1....

what am i doing wrong?? thx in advance!!