Evaluate the Integral: (x)(3^x^2) dx The exponent in the exponent is confusing me, and I'm not entirely sure how to approach this problem.
Follow Math Help Forum on Facebook and Google+
Originally Posted by Moderatelyconfused Evaluate the Integral: (x)(3^x^2) dx The exponent in the exponent is confusing me, and I'm not entirely sure how to approach this problem. $\displaystyle \int x\cdot 3^{x^2}~dx = \frac{1}{2}\int 3^{x^2}~d(x^2)$ Now recall that $\displaystyle \int a^u~du = \frac{a^u}{\ln{a}} + C$
View Tag Cloud