Integration by substitution

**nerdzor** · March 23rd 2009, 11:55 PM

$Integrate: x root (4x-3)$ using substitution u = 4x-3

Sorry, don't know how to use the codes to make it look mathematical. Where can I learn to do that?

**Jhevon** · March 24th 2009, 12:55 AM

Originally Posted by nerdzor

$Integrate: x root (4x-3)$ using substitution u = 4x-3

do as they suggest

Let $u = 4x - 3 \implies \boxed{x = \frac 14(u + 3)}$

$\Rightarrow du = 4~dx$

$\Rightarrow \frac 14 ~du = dx$

By plugging in all these pieces, we obtain the integral,

$\frac 1{16} \int (u + 3) \sqrt u~du$

now continue, hopefully you see how we got to that

Sorry, don't know how to use the codes to make it look mathematical. Where can I learn to do that?

here