$\displaystyle Integrate: x root (4x-3)$ using substitution u = 4x-3
Sorry, don't know how to use the codes to make it look mathematical. Where can I learn to do that?
do as they suggest
Let $\displaystyle u = 4x - 3 \implies \boxed{x = \frac 14(u + 3)}$
$\displaystyle \Rightarrow du = 4~dx$
$\displaystyle \Rightarrow \frac 14 ~du = dx$
By plugging in all these pieces, we obtain the integral,
$\displaystyle \frac 1{16} \int (u + 3) \sqrt u~du$
now continue, hopefully you see how we got to that
hereSorry, don't know how to use the codes to make it look mathematical. Where can I learn to do that?