y ' = x(sec x tan x) + (sec x)1 y ' = (sec x )(1 + x tan x) ** I just don't understand how they got the second step out of the first. Thanks in advance
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Originally Posted by janedoe y ' = x(sec x tan x) + (sec x)1 y ' = (sec x )(1 + x tan x) ** I just don't understand how they got the second step out of the first. Use the factoring you learned back in algebra: . . . . .x(AB) + (B)1 = B(xA + 1)
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