y ' = x(sec x tan x) + (sec x)1

y ' = (sec x )(1 + x tan x)

** I just don't understand how they got the second step out of the first.

Thanks in advance(Talking)

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- Mar 23rd 2009, 06:57 AMjanedoeI just need an explanation of derivative problem
y ' = x(sec x tan x) + (sec x)1

y ' = (sec x )(1 + x tan x)

** I just don't understand how they got the second step out of the first.

Thanks in advance(Talking) - Mar 23rd 2009, 07:00 AMstapel