Find dy/dx Need help again

**Jim Marnell** · March 22nd 2009, 07:01 PM

$x^4+3x^2y^3-y^2=5$

Thanks!

**Pinkk** · March 22nd 2009, 07:22 PM

Just follow the same thought process as the last problem you posted.

**Jim Marnell** · March 22nd 2009, 07:52 PM

$x^4+3x^2y^3-y^2=5$
$(4x^3)+[(3x^2)(3y^2dy/dx)+(y^3)(6x)]-2ydy/dx=0$
$(4x^3)+(9x^2y^2)dy/dx+(6xy^3)-(2y)dy/dx=0$
$(4x^3)+(6xy^3)=(2y)dy/dx-(9x^2y^2)dy/dx$
$(4x^3+6xy^3)/2y-9x^2y^2)=dy/dx$

Thanks for the help Pink!

**Jim Marnell** · March 22nd 2009, 07:53 PM

sorry i havnt figured out how to put a set of numbers over another set, so the / is the divide line.

**Pinkk** · March 22nd 2009, 07:54 PM

Correct.

To have a fraction like $\frac{a}{b}$ , use \frac{a}{b} inside the [tex] tags.

**matheagle** · March 22nd 2009, 08:11 PM

I use {a\over b} instead of frac
This one can be solved by explicit differentiation.
Let $w=x^2$ and then solve the quadractic equation in w.

Math Help - Find dy/dx Need help again

LinkBack

Thread Tools

Display

Find dy/dx Need help again

Is this right?

Similar Math Help Forum Discussions

Find an Equation of the Tangent Line to the parabola at the given point and find....

Given 3 points, find the area of the triangle/find the volume of the parallelepiped

How to find the find local max, min and inflection points from an integral?

Find condition that wedge may move and if it does, find acceleration?

Have dv/dx need to find dx/dt ? (have velocity w/ respect displace - find Accel?)

Search Tags