# Thread: limit how to get to a step?

1. ## limit how to get to a step?

how do i get from this step of the limit: limit of [1/(3+x)-(1/3)]/x as x approaches 0 to this step limit of 3-(3+x)/(3+x)3(x) as x approaches 0 the solution to the problem is -1/9

2. $
\begin{gathered}
\frac{1}
{{3 + x}} - \frac{1}
{3} = \frac{{ - x}}
{{9 + 3x}} \hfill \\
\frac{{\frac{{ - x}}
{{9 + 3x}}}}
{x} = \frac{{ - 1}}
{{9 + 3x}} \hfill \\
\end{gathered}$