# Math Help - Integral

1. ## Integral

x^2+x+3/(x-1)^3 . . . do I do a partial fraction decomposition and how do I go about that?

2. $\frac{x^2+x+3}{(x-1)^3}=\frac{A}{x-1}+\frac{B}{(x-1)^2}+\frac{C}{(x-1)^3}$

3. Put $u=x-1,$ written backwards as $x=u+1$ and $du=dx,$ thus the integral becomes $\int{\frac{(u+1)^{2}+u+1+3}{u^{3}}\,du},$ then do the algebra and turn that integral into many ones.