Results 1 to 3 of 3

Math Help - Integral

  1. #1
    Newbie
    Joined
    Feb 2009
    From
    Wyoming
    Posts
    13

    Integral

    x^2+x+3/(x-1)^3 . . . do I do a partial fraction decomposition and how do I go about that?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor red_dog's Avatar
    Joined
    Jun 2007
    From
    Medgidia, Romania
    Posts
    1,245
    Thanks
    1
    \frac{x^2+x+3}{(x-1)^3}=\frac{A}{x-1}+\frac{B}{(x-1)^2}+\frac{C}{(x-1)^3}
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Math Engineering Student
    Krizalid's Avatar
    Joined
    Mar 2007
    From
    Santiago, Chile
    Posts
    3,654
    Thanks
    11
    Put u=x-1, written backwards as x=u+1 and du=dx, thus the integral becomes \int{\frac{(u+1)^{2}+u+1+3}{u^{3}}\,du}, then do the algebra and turn that integral into many ones.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: August 31st 2010, 07:38 AM
  2. Replies: 1
    Last Post: June 2nd 2010, 02:25 AM
  3. Replies: 0
    Last Post: May 9th 2010, 01:52 PM
  4. Replies: 0
    Last Post: September 10th 2008, 07:53 PM
  5. Replies: 6
    Last Post: May 18th 2008, 06:37 AM

Search Tags


/mathhelpforum @mathhelpforum