The tangent to the curve y=x^2 + 4x - 5 at (1,0) is T and N is the normal to the curve y = x^2 - x + 2 at (1,2)
Hello, Jaguis!
It's quite straight-forward . . . Exactly where is your difficulty?
The tangent to the curve at (1,0) is
and is the normal to the curve at (1,2)
Find the intersection of and .
The slope of the tangent to is: .
At (1,0), the slope is: .
The equation of the tangent is: . .[1]
The slope of the tangent to is: .
At (1,2), the slope is: .
Hence, the slope of the normal is: .
The equation of the normal is: . .[2]
Now find the intersection of [1] and [2] . . .