Thread: Proving differentiability

Determine whether or not is differentiable.

Now, from what I understand, in order to show that a function of two variables is differentiable at some point , I have to show that and are continuous at and that itself is continuous at . I know that the partials are continuous for all , but how do I show that is continuous? (The problem does not ask if the function is differentiable at a specific point .) Thanks in advance.

Same question with the equation .

I think all they want is that, since , and are all differentiable, then their product and sum is differentiable.
This is not true in regards to division, like .

So since there are no points where either of those equations are undefined, the equations are continuous?

All three (x,y, x squared)are continuous everywhere
1/x is continuous everywhere except at zero, where it's not even defined.

Originally Posted by Pinkk

So since there are no points where either of those equations are undefined, the equations are continuous?

All polynomials have the property that where they are defined they are continuous (and, in fact, infinitely differentiable). That is, of course, not true for all functions.

Ah, okay. I wanted to make sure that was true for functions of two variables in three dimensions.