Are we to assume the bottom is in the xy-plane? Use cylindrical coordinates, of course.
goes from to (arctan(4/4)= arctan(1) to arctan(-4/4)), r from to , and z from 0 to 2.
Hi, I am kinda having trouble trying to find the limits for the triple integral.
Please help....
Thanks.
Integrate the function over the solid given by the figure below, if P=(-4,-4,2), Q=(-3,-3,2), R=(3,3,2), and S=(4,4,2).
integral =
(You should find the actual value when you evaluate the integral!)
Thanks a lot for the reply...
I tried to integrate the function and getting 2960/3 which is not the right answer...
okay.. first I converted to cylindrical coordinate!!!
Given, -5x+5y
so -5(r*cos(t))+5(r*sin(t))
now integrated the following function:
=> (-5(r*cos(t))+5(r*sin(t)))*r*dz*dr*dt
=> (740/3)*sqrt(2)*sin((1/4)*Pi)+(740/3)*sqrt(2)*cos((1/4)*Pi)-(740/3)*sqrt(2)*sin((5/4)
=> 2960/3