My book is telling me d/du((e^u)dy/dx) =(e^u)dy/dx + (e^u)(d2y/dx2).(dx/du) I understand where the first part has come from, but not sure how the second part was derived. Would anyone kindly provide me with an explanation?
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Originally Posted by Erghhh My book is telling me d/du((e^u)dy/dx) =(e^u)dy/dx + (e^u)(d2y/dx2).(dx/du) I understand where the first part has come from, but not sure how the second part was derived. Would anyone kindly provide me with an explanation? This will make it clear Differnetiation of dy/dx wrt u will be given by (using chain rule) ------------------------------------------ So differnetiation will be
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