My book is telling me

d/du((e^u)dy/dx)

=(e^u)dy/dx + (e^u)(d2y/dx2).(dx/du)

I understand where the first part has come from, but not sure how the second part was derived. Would anyone kindly provide me with an explanation?

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- March 21st 2009, 07:41 AMErghhhSolving differential equations using a change of variable
My book is telling me

d/du((e^u)dy/dx)

=(e^u)dy/dx + (e^u)(d2y/dx2).(dx/du)

I understand where the first part has come from, but not sure how the second part was derived. Would anyone kindly provide me with an explanation? - March 21st 2009, 08:43 AMADARSHErghhhhhhh....:p