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About LinkBacksFind dy/dx by implicit differentiation
6(sin (8x))(cos (5y) = 4
I tried doing it and came up with
(tan (8x))(5 tan(5)), but this is not correct...
How did you arrive at your answer? What were your steps?Originally Posted by tradar
Applying the Product Rule and the Chain Rule, the differentiation would appear to start as:
. . . . .6*(8 cos(8x) (dx/dx))*cos(5y) + 6*(sin(8x))*(-5 cos(5y) sin(5y) (dy/dx)) = 0
. . . . .48 cos(8x) cos(5y) - 30 sin(8x) sin(5y) (dy/dx) = 0
. . . . .48 cos(8x) cos(5y) = 30 sin(8x) sin(5y) (dy/dx)
Divide through to isolate "dy/dx".
How did you arrive at your answer? What were your steps?
Applying the Product Rule and the Chain Rule, the differentiation would appear to start as:
. . . . .6*(8 cos(8x) (dx/dx))*cos(5y) + 6*(sin(8x))*(-5 cos(5y) sin(5y) (dy/dx)) = 0
. . . . .48 cos(8x) cos(5y) - 30 sin(8x) sin(5y) (dy/dx) = 0
. . . . .48 cos(8x) cos(5y) = 30 sin(8x) sin(5y) (dy/dx)
Divide through to isolate "dy/dx".cos(5y)}{30sin(8x)sin(5y)} = \frac{8cot(8x)cot(5y)}{5})
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