Find dy/dx by implicit differentiation

6(sin (8x))(cos (5y) = 4

I tried doing it and came up with

(tan (8x))(5 tan(5)), but this is not correct...

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- Mar 21st 2009, 06:59 AMtradarImplicit Differentiation
Find dy/dx by implicit differentiation

6(sin (8x))(cos (5y) = 4

I tried doing it and came up with

(tan (8x))(5 tan(5)), but this is not correct... - Mar 21st 2009, 07:10 AMstapel
How did you arrive at your answer? What were your steps?

Applying the Product Rule and the Chain Rule, the differentiation would appear to start as:

. . . . .6*(8 cos(8x) (dx/dx))*cos(5y) + 6*(sin(8x))*(-5 cos(5y) sin(5y) (dy/dx)) = 0

. . . . .48 cos(8x) cos(5y) - 30 sin(8x) sin(5y) (dy/dx) = 0

. . . . .48 cos(8x) cos(5y) = 30 sin(8x) sin(5y) (dy/dx)

Divide through to isolate "dy/dx". :D - Mar 21st 2009, 08:35 AMtradar
8(tan8xtan5y) ?

- Mar 21st 2009, 08:40 AMe^(i*pi)