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Math Help - A hard inverse tan partial derivative

  1. #1
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    A hard inverse tan partial derivative

    a is a constant. My brain is fried from two days of aerodynamics, i can`t get this one.
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  2. #2
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    Inverse tan

    Hello flawless
    Quote Originally Posted by flawless View Post
    a is a constant. My brain is fried from two days of aerodynamics, i can`t get this one.
    z = \tan^{-1}u

    \Rightarrow \tan z = u

    \Rightarrow \frac{du}{dz} = \sec^2 z = 1 + \tan^2 z = 1 + u^2

    \frac{dz}{du}= \frac{1}{1+u^2}

    For the partial derivative, assume y is constant (as well as a) and differentiate with respect to x. Can you complete it now?

    Grandad
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