what is the limit limit as x-> infinity of
(sin x) / sqrt(x)
i know lim (sin x)/x = 1
but how do i find the one above???
I hope you don't know that! sin(x)/x goes to 1 as x goes to 0 but your limit is for x going to infinity. You know that sin(x) is never larger than 1 nor less than -1: $\displaystyle \frac{-1}{x}\le\frac{sin x}{x}\le\frac{1}{x}$. Now, what happens to those end terms as x goes to infinity?
Moo's hint would be relevant if the limit were as x goes to 0. I think you mislead him!