Results 1 to 3 of 3

Math Help - Differentiation of Complex Numbers

  1. #1
    Junior Member
    Joined
    Mar 2008
    Posts
    33

    Differentiation of Complex Numbers

    a)
    Find the deriviative of the following function and specify the domain of this derviative

    f(z)=[Log(4z-i)]/z^2

    b)
    Use the defintion of the derivative to prove that the function

    f(z)=Im z -2i

    is not differentiable at 1+2i



    a)
    Now I have attempted this question using the quotient Rule and ended up with something like this

    f'(z)=[z^2(4/4z-i)-(2z)Log(4z-i)](z^2)^2
    =[4z^2/(4z-i)-2zLog(4z-i)]/z^4

    Now i am not sure on how to simplfy it further. The value thats getting to me is the most is the 4z^2/(4z-i)/z^4. Hope fully some one can show me how to do it and also help on what the domain is.


    b)
    For this part i know i am to use the formula

    [f(z)-f(a)]/z-a

    But how to do it is really confusing. I think as well that the Imz part is making it probably seem harder then it actually is.


    Hopefully someone can point me in the right direction

    Thanx

    Bex
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Jan 2007
    Posts
    42
    b)

    if you think of z as x+iy

    im(z) = y

    so f(z) =f (x,y) = y - 2i

    now try to find two paths along which, the limit in the defn. of the derivative gives two values (show that the limiting value is not unique)
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Mar 2008
    Posts
    33
    Ok I understand what you mean, but if i were to choose 2 sequences, say 1/n and -1/n, how can i do f(1/n) when in the equation f(z)=y-2i there is no z value. Even if the sequences I've chosen are wrong, I am going to end up at some point doing f(1+2i), and again there is no z value so will end up as 0. Not sure where to go from here. Help

    Bex


    Quote Originally Posted by qpmathelp View Post
    b)

    if you think of z as x+iy

    im(z) = y

    so f(z) =f (x,y) = y - 2i

    now try to find two paths along which, the limit in the defn. of the derivative gives two values (show that the limiting value is not unique)
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. raising complex numbers to complex exponents?
    Posted in the Advanced Math Topics Forum
    Replies: 10
    Last Post: March 25th 2011, 11:02 PM
  2. Replies: 1
    Last Post: September 27th 2010, 04:14 PM
  3. Replies: 2
    Last Post: February 7th 2009, 07:12 PM
  4. differentiation and complex numbers
    Posted in the Calculus Forum
    Replies: 10
    Last Post: August 15th 2007, 09:36 PM
  5. Replies: 1
    Last Post: May 24th 2007, 04:49 AM

Search Tags


/mathhelpforum @mathhelpforum