Can somebody ,show me how to work this out f(t)= 1/10 te^0.1t thanks if you can help
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Originally Posted by Jaffa Can somebody ,show me how to work this out f(t)= 1/10 te^0.1t thanks if you can help $\displaystyle u = t$ ... $\displaystyle du = dt$ $\displaystyle dv = 0.1e^{0.1t}$ ... $\displaystyle v = e^{0.1t}$ $\displaystyle \int 0.1t \cdot e^{0.1t} \, dt = te^{0.1t} - \int e^{0.1t} \, dt$ can you finish?
Should it be =te^o.1t -e^0.1t/0.1 after this, if it is right ,I am lost, and what about the 1/10 at the start
Originally Posted by Jaffa Should it be =te^o.1t -e^0.1t/0.1 after this, if it is right ,I am lost, and what about the 1/10 at the start note that $\displaystyle \frac{1}{10} = 0.1$ $\displaystyle \int 0.1 t e^{0.1t} \, dt = te^{0.1t} - 10e^{0.1t} + C$
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