1. ## another sequence Help please

An= n[ln(n+1) - lnn]

does it equal e

2. Originally Posted by twilightstr
An= n[ln(n+1) - lnn]

does it equal e
It doesn't equal e...but you have the right idea.

Note that $a_n=n\left(\ln(n+1)-\ln(n)\right)=n\ln\left(\frac{n+1}{n}\right)=\ln\l eft[\left(1+\frac{1}{n}\right)^n\right]$

Now, $\lim \left(1+\frac{1}{n}\right)^n=e$

So, $\lim a_n=\dots$

Does this make sense?