After my Trig sub , i get when i differentiate that, i do not get my initial integral which is a problem , can someone do this integral step by step please
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Originally Posted by Larrioto After my Trig sub , i get when i differentiate that, i do not get my initial integral which is a problem , can someone do this integral step by step please Here is how I approached it x =cos(t) dx = - sin(t)dt I wont go further before you try it
this is false, because the exponant is not 3, but 3/2
Originally Posted by Larrioto this is false, because the exponant is not 3, but 3/2
The error is here..... Originally Posted by ADARSH Here is how I approached it x =cos(t) dx = - sin(t)dt I wont go further before you try it It's times and not subtraction maybe try the two half angle formulas here instead of going with tangent times sine
Originally Posted by ADARSH Here is how I approached it x =cos(t) dx = - sin(t)dt I wont go further before you try it *I dont understand it
It looks fine. I guess through trig the integrand can be either. I figured you had to have a mistake, but they both seem ok. Now you need to get back to the x.
Originally Posted by ADARSH Thus we get our answer
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