The question is:
Find the Cartesian form of the equation for the plane that is perpendicular to the space curve
at the point P(32, -32, 16).
Now the simple part of course, once I have the normal (n) to the curve at P, I can construct a plane equation via where (the vector from the plane's origin (P) to any point Q).
Of course, I can find the derivative of r(t), which is:
That will give me the tangent vector at any time t.
I know that t = 16, from the 'k' component, so I can evaluate
But I need the normal vector (perpendicular to the curve).