Given the points A=(-1,1,0), B=(1,3,0), C=(0,3,-1) and D=(1,2,3)
What is the distance between the plane through A,B, C and point D?
anyone can give me a hint?
Thanks
Hint: Once you have the equation of the plane in the form $\displaystyle ax + by + cz + d =0$ then the distance between that plane and the point $\displaystyle P(x_0,y_0,z_0)$ is given by
$\displaystyle \frac{|a x_0 + b y_0 + c z_0 + d |}{\sqrt{a^2+b^2+c^2}}$