I have a triple integral in terms of x,y and z and need to convert it to spherical coordinates.
it is the integral from 0 to 2 and then from 0 to (4 - x^2)^(1/2) inner bounds from 0 to (4 - x^2 - y^2)^(1/2) of (x^2 + y^2 + z^2)^(1/2) dz dy dx
Since the integral is of roe spherical will work well I think!!!
So, we will integrate roe^3 sin phi d roe d phi d theta
My lower bounds must be all zeros.
Can someone please go through the thinking process to determine my upper bounds?
Once I have these I can do the integration no problem. Without them I am stuck! Frostking