# Partial derivative

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• March 16th 2009, 11:44 AM
mr_motivator
Partial derivative
Not sure how to go about this, can anyone help?

A function is defined by f (x, y, z) = -sin (2 y z x) find http://ta2.maths.ed.ac.uk:8080/maple...cfkdnafcln.gif.
• March 16th 2009, 12:21 PM
Danny
Quote:

Originally Posted by mr_motivator
Not sure how to go about this, can anyone help?

A function is defined by f (x, y, z) = -sin (2 y z x) find http://ta2.maths.ed.ac.uk:8080/maple...cfkdnafcln.gif.

$\frac{\partial f}{\partial y} = - \cos(2 x y z) 2 x z$, then

$\frac{\partial^2 f}{\partial y \partial z} = -2 \frac{\partial}{\partial z} \left( x z\cos(2 x y z) \right)$ then use the product rule and chain rule again.