$\displaystyle \int \arccos(2x)$
Follow Math Help Forum on Facebook and Google+
$\displaystyle \int \arccos(2x) \, dx $ integration by parts ... $\displaystyle u = \arccos(2x)$ ... $\displaystyle dv = dx$ $\displaystyle du = -\frac{2}{\sqrt{1 - 4x^2}} \, dx$ ... $\displaystyle v = x$
View Tag Cloud