Thread: [SOLVED] Integration

$\displaystyle \int \arccos(2x)$

$\displaystyle \int \arccos(2x) \, dx
$

integration by parts ...

$\displaystyle u = \arccos(2x)$ ... $\displaystyle dv = dx$

$\displaystyle du = -\frac{2}{\sqrt{1 - 4x^2}} \, dx$ ... $\displaystyle v = x$