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Thread: [SOLVED] Integration

  1. Mar 15th 2009, 04:41 PM #1
    vinson24
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    [SOLVED] Integration

    \int \arccos(2x)
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  2. Mar 15th 2009, 04:46 PM #2
    skeeter
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    \int \arccos(2x) \, dx<br />

    integration by parts ...

    u = \arccos(2x) ... dv = dx

    du = -\frac{2}{\sqrt{1 - 4x^2}} \, dx ... v = x
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