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Math Help - Parametric equations

  1. #1
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    Parametric equations

    A function is defined parametrically by x=5t, y=t^5 + (20t)/3

    a)Find dy/dx in terms of t

    b) given that dy/dx=1, show that t + 4t - 2=0



    Ok for part a i do

    dx/dt = 10t

    dy/dt= 5t^4 + (180t)/9
    =5t^4 + 20t


    dy/dx = (5t^4 + 20t)/10t
    =(t^4 + 4t)/2t

    could anyone confirm this to be right?

    also how do i do the next part?
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  2. #2
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    Quote Originally Posted by djmccabie View Post
    A function is defined parametrically by x=5t, y=t^5 + (20t)/3

    a)Find dy/dx in terms of t

    b) given that dy/dx=1, show that t + 4t - 2=0



    Ok for part a i do

    dx/dt = 10t

    dy/dt= 5t^4 + (180t)/9
    =5t^4 + 20t


    dy/dx = (5t^4 + 20t)/10t
    =(t^4 + 4t)/2t

    could anyone confirm this to be right?

    also how do i do the next part?
    So far, fine. Of course that is only defined for t\ne 0. And you can cancel the t in numerator and denominator to simplify.

    To do the second part, set that equal to 1!
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