A function is defined parametrically by x=5t², y=t^5 + (20t³)/3
a)Find dy/dx in terms of t
b) given that dy/dx=1, show that t³ + 4t - 2=0
Ok for part a i do
dx/dt = 10t
dy/dt= 5t^4 + (180t)/9
=5t^4 + 20t²
dy/dx = (5t^4 + 20t²)/10t
=(t^4 + 4t²)/2t
could anyone confirm this to be right?
also how do i do the next part?