r = 5sin(4theta)

the area is

please get answer

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- Mar 15th 2009, 11:14 AMtiga killaFind the area inside one leaf of the rose:
r = 5sin(4theta)

the area is

please get answer - Mar 15th 2009, 11:37 AMskeeter

I've noted that you've been asking a questions about polar calculus ... what, exactly, do you know about finding area of a polar region?

do you know what the graph of $\displaystyle r = 5\sin(4\theta)$ looks like?

what would be the limits of integration for a single petal?