1. ## another EZ Integral

By easy, I mean for people that are good at this. I spent 30 minutes thinking prior to posting here

$
\frac{1}{xln^3x}dx
$

This looks like u = ln(x) or something but that extra x is messing me up

2. Originally Posted by TYTY
By easy, I mean for people that are good at this. I spent 30 minutes thinking prior to posting here

$
\frac{1}{xln^3x}dx
$

This looks like u = ln(x) or something but that extra x is messing me up
You have the correct substituion

$u=\ln(x) \implies du=\frac{1}{x}dx$

putting these into the integral gives

$\int \frac{1}{u^3}du=\int u^{-3}du$

Good luck.

3. Originally Posted by TheEmptySet
You have the correct substituion

$u=\ln(x) \implies du=\frac{1}{x}dx$

putting these into the integral gives

$\int \frac{1}{u^3}du=\int u^{-3}du$

Good luck.
I'm actually a little bit upset that it was that easy. Thank you though - I do appreciate it