Results 1 to 3 of 3

Math Help - Trig integrals

  1. #1
    Junior Member
    Joined
    Mar 2009
    Posts
    62

    Trig integrals

    Find the indefinite integral:

    h(u) = sin^2(1/12u)

    This is what I have:

    sin^2(1/12u) = 1/2( 1 - cos( 1/6u))

    sin^2(1/12u) = 1/2 -1/2 cos(1/6u) dx

    = 1/12u-1/4sin(1/6) +c

    I am lost, please help!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Apr 2005
    Posts
    15,547
    Thanks
    1395
    Quote Originally Posted by mark090480 View Post
    Find the indefinite integral:

    h(u) = sin^2(1/12u)
    Is "1/12u" supposed to be "1/(12u)" or "(1/12)u"?

    I will assume you meant "(1/12)u".


    This is what I have:

    sin^2(1/12u) = 1/2( 1 - cos( 1/6u))

    sin^2(1/12u) = 1/2 -1/2 cos(1/6u) dx

    = 1/12u-1/4sin(1/6) +c
    Please don't just write "=" like that. That means that what you are writing now is equal to what you had on the previous line. And that is not true.

    I am lost, please help!
    Why "(1/12)u"? The anti-derivative of (1/2) is (1/2)u. How did you get the "1/4" in front of "cos((1/6)u"?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Mar 2009
    Posts
    62
    No, I mean (1/12u) or (0.8333333u)

    Thanks,

    -Mark.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Trig Integrals...
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: July 18th 2010, 12:10 PM
  2. Trig integrals
    Posted in the Calculus Forum
    Replies: 9
    Last Post: June 23rd 2009, 07:38 PM
  3. integrals with trig
    Posted in the Calculus Forum
    Replies: 5
    Last Post: April 20th 2009, 12:21 PM
  4. trig integrals
    Posted in the Calculus Forum
    Replies: 6
    Last Post: February 24th 2009, 04:43 PM
  5. Trig sub integrals
    Posted in the Calculus Forum
    Replies: 4
    Last Post: September 9th 2008, 06:09 PM

Search Tags


/mathhelpforum @mathhelpforum