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Math Help - [SOLVED] integration by trig substitution

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    [SOLVED] integration by trig substitution

    \int \frac{dx}{sqrt(x^2-4)}
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    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by vinson24 View Post
    \int \frac{dx}{sqrt(x^2-4)}
    Note that \int\frac{\,dx}{\sqrt{x^2-4}}=\int\frac{\,dx}{\sqrt{4\left(\frac{x^2}{4}-1\right)}}=\tfrac{1}{2}\int\frac{\,dx}{\sqrt{\left  (\frac{x}{2}\right)^2-1}}

    Can you continue from here?
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by vinson24 View Post
    \int \frac{dx}{\sqrt{x^2-4}}
    alternatively, a trig substitution of x = 2 \sec \theta could work. well, not really alternatively....
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    yes i can thank you
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