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Math Help - Determine divergence or convergence by Alternating Series Test

  1. #1
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    Determine divergence or convergence by Alternating Series Test

    Series , n=1, (-1)^(n+1) (4n-1)/4n
    I need to solve this by Alternating Test, and according to it a(n+1) is greater than a(n), which means that the test failed.

    Is this correct?
    Thank you.
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  2. #2
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    Hello, oceanmd!

    \sum^{\infty}_{n=1}\frac{(\text{-}1)^{n+1}(4n-1)}{4n}

    I need to solve this by Alternating Test, and according to it: . a_{n+1} \:>\:a_n

    . . . which means that the series diverges.

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  3. #3
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    Thank you

    Thank you very much.
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