Series , n=1, (-1)^(n+1) (4n-1)/4n I need to solve this by Alternating Test, and according to it a(n+1) is greater than a(n), which means that the test failed. Is this correct? Thank you.
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Hello, oceanmd! $\displaystyle \sum^{\infty}_{n=1}\frac{(\text{-}1)^{n+1}(4n-1)}{4n}$ I need to solve this by Alternating Test, and according to it: .$\displaystyle a_{n+1} \:>\:a_n$ . . . which means that the series diverges.
Thank you very much.
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