# Determine divergence or convergence by Alternating Series Test

• March 14th 2009, 07:27 PM
oceanmd
Determine divergence or convergence by Alternating Series Test
Series , n=1, (-1)^(n+1) (4n-1)/4n
I need to solve this by Alternating Test, and according to it a(n+1) is greater than a(n), which means that the test failed.

Is this correct?
Thank you.
• March 14th 2009, 09:28 PM
Soroban
Hello, oceanmd!

Quote:

$\sum^{\infty}_{n=1}\frac{(\text{-}1)^{n+1}(4n-1)}{4n}$

I need to solve this by Alternating Test, and according to it: . $a_{n+1} \:>\:a_n$

. . . which means that the series diverges.

• March 15th 2009, 11:55 AM
oceanmd
Thank you
Thank you very much.