Series , n=1, (-1)^(n+1) (4n-1)/4n

I need to solve this by Alternating Test, and according to it a(n+1) is greater than a(n), which means that the test failed.

Is this correct?

Thank you.

- Mar 14th 2009, 06:27 PMoceanmdDetermine divergence or convergence by Alternating Series Test
Series , n=1, (-1)^(n+1) (4n-1)/4n

I need to solve this by Alternating Test, and according to it a(n+1) is greater than a(n), which means that the test failed.

Is this correct?

Thank you. - Mar 14th 2009, 08:28 PMSoroban
Hello, oceanmd!

Quote:

$\displaystyle \sum^{\infty}_{n=1}\frac{(\text{-}1)^{n+1}(4n-1)}{4n}$

I need to solve this by Alternating Test, and according to it: .$\displaystyle a_{n+1} \:>\:a_n$

. . . which means that the series*diverges*.

- Mar 15th 2009, 10:55 AMoceanmdThank you
Thank you very much.