Find the function f where f(x) is f(x)=∫((x-1)^2)/(x^2+1)) f(x)dx - c
Differentiate both sides of the given equation:
$\displaystyle f'(x) = \frac{(x-1)^2}{x^2+1} f(x)$
Now re-arrange and integrate: $\displaystyle \int \frac{f'(x)}{f(x)} \, dx = \int \frac{(x-1)^2}{x^2+1} \, dx$.
The integral on the right hand side is found using the suggestion in the previous reply.