# Power Series Question

• Mar 12th 2009, 06:31 PM
thehollow89
Power Series Question
Power series from 1 to infinity of (n^n)*x^n? I applied the ratio test:
((n+1)^(n+1)x^(n+1))/((n^n)*x^n) = ((n+1)^(n+1)*x)/(n^n) and after taking the limit of n->infinity I got nx which goe s to infinity. I think I messed up, any help? (Rock)
• Mar 12th 2009, 07:38 PM
Soroban
Hello, thehollow89!

The algebra of the Ratio Test is very tricky . . .

Quote:

$\displaystyle \sum^{\infty}_{n=1} n^nx^n$

We have: .$\displaystyle R \;=\;\frac{a_{n+1}}{a_n} \;=\;\frac{(n+1)^{n+1}x^{n+1}} {n^nx^n} \;=\;\frac{(n+1)(n+1)^n}{n^n}\,x$

. . . . . . . . . $\displaystyle = \;(n+1)\left(\frac{n+1}{n}\right)^n\!\!x \;=\;(n+1)\left(1 + \frac{1}{n}\right)^n\!\!x$

$\displaystyle \text{Take the limit: }\:\lim_{n\to\infty}\left[(n+1)\left(1 + \frac{1}{n}\right)^n x\right]$

. . . . . . . . $\displaystyle =\;\underbrace{\left[\lim_{n\to\infty}(n+1)\right]}_{\text{This is }\infty}\cdot\underbrace{\left[\lim_{n\to\infty}\left(1 + \frac{1}{n}\right)^n\,\right]}_{\text{This is }e}\cdot x$

. . . . . . . . $\displaystyle =\;\; \infty\cdot e\cdot x \;\;=\;\;\infty\quad\hdots\quad\text{The series diverges.}$