Could someone guide me through the steps of integrating 4x.e^[-2ln(x)] thanks
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Originally Posted by matty888 Could someone guide me through the steps of integrating 4x.e^[-2ln(x)] thanks $\displaystyle \int 4xe^{-2\ln(x)}dx=\int 4xe^{\ln(x^{-2})}dx=\int 4x\cdot x^{-2}dx=4\int\frac{1}{x}dx=4\ln|x|+c$
Thanks TheEmptySet I was missing out on the log&e bit
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