∫(4x²-11x+4)/(x³-3x²+2x) dx

i know the bottom part breaks up into

x(x²-3x+2) = x(x-2)(x-1)

where do i go form there?

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- Mar 11th 2009, 10:10 PMhlpplzPartial Fractions
∫(4x²-11x+4)/(x³-3x²+2x) dx

i know the bottom part breaks up into

x(x²-3x+2) = x(x-2)(x-1)

where do i go form there? - Mar 11th 2009, 10:27 PMJhevon
- Mar 11th 2009, 10:27 PMADARSH
- Mar 11th 2009, 10:43 PMhlpplz
ok so i multiplied by the LCD and got

4x²-11x+4 = A(x-2)(x-1) + B(x)(x-1) + C(x)(x-2)

4x²-11x+4 = A(x²-3x+2) + B(x²-x) + C(x²-2x)

isolating x² = A + B + C = 4

isolating x = -3A - B - 2C = -11

isolating # = 2A = 4

solving for A,B,C i got

A= 2, B=-7, C=9

∫ A/x + B/(x-2) + C/(x-1) dx

∫ 2/x - 7/(x-2) + 9/(x-1) dx

2∫ 1/x - 7∫ 1/(x-2) + 9∫ 1/(x-1) dx

2ln⎮x⎮ - 7ln⎮x-2⎮ + 9ln⎮x-1⎮

Good? - Mar 11th 2009, 10:46 PMADARSH
- Mar 11th 2009, 10:49 PMhlpplz
Thank you very much (Rock)