Nevermind, I figred it out.. The limits of integration were the two intersection points of both of the graphs.
I keep on getting the wrong answer on this problem..
Find the area between the curves of y=lnx and the line y = x-2, the answer is 1.949, but I always get 1.917...
So I used the problem as a dy problem, thus x = e^y, Y1, and x = y+2, Y2..
I took the integral from -2 to 1 of Y2 - Y1 and I got 1.917, what am I doing wrong?
I suppose there is only one way to solve:
using software to find out the two intersections of the curves
y=lnx and y=x-2
Thank you for Winplot .. i can find out the points by using it and they are
(0.15859 , -1.84141) and (3.14619 , 1.14619)
The next step should be integrating lnx - (x-2)
The result is xlnx + x - x^2/2
Sub. these values and the ans is 1.949 (4 sfg)