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ahhh $\displaystyle y = x^{2 - x} \Rightarrow \ln y = (2 - x) \ln (x) \Rightarrow \frac{1}{y} \frac{dy}{dx} = - \ln (x) + \frac{2-x}{x}$$\displaystyle
$
Ohhhh...how can you tell when you need to use logarithmic differentation?
I understand the process now. Thanks!!