Integral

integral (2x^3-4x-8)/((x^2-x)(x^2+4))

Thanksss!!!

Quote:

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Originally Posted by alex.caine

integral (2x^3-4x-8)/((x^2-x)(x^2+4))

Thanksss!!!

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$\displaystyle
\frac{2(x^3-2x-4)}{x(x-1)(x^2+4)} = \frac{A}{x} + \frac{B}{x-1} + \frac{Cx+D}{x^2+4}
$

complete the partial fraction decomposition, then integrate.