Printable View
integral (2x^3-4x-8)/((x^2-x)(x^2+4)) Thanksss!!!
Quote: Originally Posted by alex.caine integral (2x^3-4x-8)/((x^2-x)(x^2+4)) Thanksss!!! $\displaystyle \frac{2(x^3-2x-4)}{x(x-1)(x^2+4)} = \frac{A}{x} + \frac{B}{x-1} + \frac{Cx+D}{x^2+4} $ complete the partial fraction decomposition, then integrate.