Integral

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Mar 11th 2009, 10:27 AM
alex.caine

Integral

integral (2x^3-4x-8)/((x^2-x)(x^2+4))

Thanksss!!!
Mar 11th 2009, 10:39 AM
skeeter

Quote:

Originally Posted by alex.caine

integral (2x^3-4x-8)/((x^2-x)(x^2+4))

Thanksss!!!

$<br /> \frac{2(x^3-2x-4)}{x(x-1)(x^2+4)} = \frac{A}{x} + \frac{B}{x-1} + \frac{Cx+D}{x^2+4}<br />$

complete the partial fraction decomposition, then integrate.

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