I'm desperately stuck on the following integral:
Integral: x^5*e^(-1/2x^2)
Thanks
$\displaystyle I=\int x^5 e^{\frac{-x^2}{2}}dx$
Take $\displaystyle u=x^5, dv=e^{\frac{-x^2}{2}}$
So $\displaystyle du=5x^4, v=\frac{e^{\frac{-x^2}{2}}}{-x}$
We want I = uv - int(v)du
So $\displaystyle I=-x^4 e^{\frac{-x^2}{2}} + \int 5x^3 e^{\frac{-x^2}{2}}$
etc...